思路：单调递减栈，找「上一个比当前价格大的元素索引」。正序遍历，弹出所有 ≤ 当前价格的索引；跨度 = 当前索引 - 栈顶索引（栈空则为 当前索引 + 1）。
The approach had two parts. The extension would attempt to modify a JavaScript file that was always shipped with every request: nozzle.js.
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Merrett said parishioners will be "thrilled" if the flooding scheme is scrapped.
FirstFT: the day's biggest stories
這位70歲的微軟聯合創辦人並未被任何愛潑斯坦案的受害者指控有不當行為。